Three years ago A's age was double of B's age. Seven years hence, the sum of their
ages will be 83 years. Find the present
age of A?​

present Age of " A " will be (x) = 45 years

present Age of " B " will be (y) = 24 years

Step-by-step explanation:

Age of " A " = x years

Age of " B " = y years

(Three years ago A's age was double of B's age.)

==> (x-3) = 2 * (y-3)

==> x - 2y = -6 + 3

==> x - 2y = -3 (1)

(Seven years hence, the sum of their ages will be 83 years )

==> (x+7)+(y+7) = 83

==> x + y = 83 - 14

==> x + y = 69 (2)

Subtract equ.(1) & equ(2)

==> -2y - y = -3 - 69

==> -3y = -72

==> y = -72/(-3)

==> y = 24

Keep value of y in equ(2)

==> x + 24 = 69

==> x = 69 - 24

==> x = 45

57 732

step-by-step explanation:

i dont really.know

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)