What's ƒ(g(x)) if ƒ(x) = 3x + 7 and g(x) =6x – 5?

18x^2 + 27x - 35

Step-by-step explanation:

f(g(x)) means function f times function g. substitute for f and g, which gets you (3x+7)(6x-5). Now, multiply using the distributive property.

3x * 6x = 18x^2

3x * -5 = -15x

7*6x = 42x

7 * -5 = -35

The equation then becomes 18x^2 - 15x + 42x - 35. Simplify the equation.

18x^2 stays, -15x and 42x combine to make 27x, and the -35 stays too.

Finally, you get the equation, 18x^2 + 27x -35.

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answer: i literally just answered this question but they want me to do it again

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