A, b,c, d,x, y,z, w are digits between 1-8. Find abcd and xyzw, both 4-digit numbers without any repeating numbers, such that

4*abcd = xyzw

git no. and how to prove it?

Lets say the number is written as ABCD (1000a+100b+10c+d).

Multiplying it by 4, gives you DCBA (1000d+100c+10b+a)

By divisibility of 4, BA is a two-digit number divisible by 4.

Now, the largest possible value of ABCD is 2499, because anything more will result in a five - digit number when multiplied by 4.

Out of the two possibilites 1 and 2 for A, [3] follows that A is even, so 2.

From [5], D is either 8 or 9. However, since D times 4 would end in 2, D is 8.

Using [2], 4000a+400b+40c+4d = 1000d+100c+10b+a, which would simplify to 2c-13b = 1 after substituting A = 2 and D = 8.

The only possible value of (b,c) where they would both be single - digit integers is (1,7). Also to note from [3], B is odd. And from [4], B is either 1 or 3.

The answer you're looking for is 2178, multiplied by 4 gives 8712.

Step-by-step explanation:

answer: 4

step-by-step explanation:

where is the figure