Can someone help me with this?

Step-by-step explanation:

Quadrilateral EFGH is a rectangle.

Therefore, measure of all interior angle of the rectangle = 90°

7). m∠FEG + m∠GEH = 90°

    57° + m∠GEH = 90°

    m∠GEH = 90° - 57°

    m∠GEH = 33°

Diagonal of the rectangle are equal in measure and bisect each other.

8). m(FH) = m(FK) + m(KH)

               = 32 + 32 [Since, FK ≅ KH]      

               = 64

9). m∠FGH + m∠EFG = 90° + 90°

                                   = 180°

MNOP is a Rhombus, so the diagonals will be perpendicular and bisect each other.

10). m∠MRN = 90°

11). m(PR) = 12

    Therefore, m(RN) = 12

"Diagonals of a rhombus bisect the opposite angles"

12). m(∠PON) = 124°

   Therefore, m(∠POM) = 124°

"ABCD is an isosceles Trapezoid"

13). Therefore, ∠C ≅ ∠D

14). AB║CD

15). AD ≅ BC

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.

a orange at the grocery store idk what other product that could be