Jane was running for 2 hours and 25 minutes and reached her journey at 2:05pm. Calculate the time she started.

11:40 am

Step-by-step explanation:

First, I started by subtracting 5 minutes from the additional 25 minutes of running that couldn’t fit into another hour. That would bring the running time to 2 hours and 20 minutes and the end time to 2:00 pm. Take away another 2 hours and you would be left with 20 minutes, with a start time of 12:00 pm. Get rid of the last 20 minutes and you get the start time as 11:40 am.

Check:

11:40 + 2 hours = 1:40 pm

1:40 + 20 minutes = 2:00 pm

2:00 + 5 minutes = 2:05

This is correct

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

lo.lll

step-by-step explanation: