What is the area of triangle ABC? a \large 6\sqrt{3} square units b \large 18\sqrt{3} square units c \large 36\sqrt{3} square units d \large 72\sqrt{3} square units

question isn't clear but I believe you are asking for the area of triangle ABC given sides a, b, c

We use the example question:

Find the area (in square units) of the triangle described.

a = 49mm, b = 33mm, c = 18mm

Answer and explanation:

We apply Heron's formula to solve the area of a triangle given the sides of the triangle a, b, c

A= √s(s-a)(s-b)(s-c)

Where A = area of triangle in square units

s= semiperimeter(a+b+c/2) of a triangle

a, b, c= lengths of the sides of the triangle

Therefore area of triangle =√50(50-49)(50-33)(50-18)

= √27200

=164.92mm²

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

-18

step-by-step explanation:

because mean value defines that total sum value over total number of set