A field of grass feeds 28 cows for 6 days. How many days would the same field feed 21 cows?

Step-by-step explanation:

28 cows × 6 days = 168 cow-days

(168 cow-days)/(21 cows) = 8 days

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

24/56=hx^7

step-by-step explanation: