In the given figlie, De and DF are perpendiculas down on Ba and BC Lespectively, such that De = df
show that A DEB = dfb

Ans​

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2

step-by-step explanation:

the true ones are a b and d

do your own work and don"t cheat.

step-by-step explanation:

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: