Add the following Expressions ( Step by step )

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1. x³y² + 4x²y³ + 7y⁴ + x⁴

2. a² + b² + c² + 2ab + 2bc + 3ca

Step-by-step explanation:

1. x³y² + x²y³ + 3y⁴ and x⁴ + 3x²y³ + 4y⁴

= x³y² + x²y³ + 3y⁴ + x⁴ + 3x²y³ + 4y⁴

= x³y² + x²y³ + 3x²y³ + 3y⁴ + 4y⁴ + x⁴

= x³y² + 4x²y³ + 7y⁴ + x⁴

2. a² + 3ab - bc, b² + 3bc - ca and c² + 3ca - ab

= a² + 3ab - bc + (b² + 3bc - ca) + (c² + 3ca - ab)

= a² + 3ab - bc + b² + 3bc - ca + c² + 3ca - ab

= a² + b² + c² + 3ab - ab + 3bc - bc + 3ca - ca

= a² + b² + c² + 2ab + 2bc + 3ca

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.