What is the product of ( 8 – j10 ) and ( 6 + j4) in rectangular form? a) 48 – j 60
b) 88 – j 28
c) 38 + j 28
d) 48 + j 60​

b

Step-by-step explanation:

Given

(8 - j10)(6 + j4) ← expand factors using FOIL

= 48 + j32 - j60 - j²40 [ j² = - 1 ]

= 48 - j28 + 40

= 88 - j28 → b

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18