Three red, ten white, five blue and two green counters are put into a bag, and one is picked at random. Calculate the probability that it is: i) a white counter

ii) a red counter

iii) Are the outcomes equally likely?

(i) 1/2

(ii) 3/20

Step-by-step explanation:

(i) given total number of white counters = 10

total outcomes = 20 (3+10+5+2)

so it's 10/20

by simplifying it we get 1/2

(ii) given total number of red counters = 3

so it's 3/20

question is incomplete.

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i