Solve for x and y 5x + 3y=35, 2x+4y=28​

Step-by-step explanation:

Let's solve your system by substitution.

5x+3y=35;2x+4y=28

Step: Solve 5x+3y=35 for x:

5x+3y=35

5x+3y+−3y=35+−3y(Add -3y to both sides)

5x=−3y+35

5x/ 5 = −3y+35/ 5  (Divide both sides by 5)

Step: Substitute  −3/ 5 y+7 for x in 2x+4y=28:

2x+4y=28

2( −3/ 5 y+7)+4y=28

14/ 5 y+14=28   (Simplify both sides of the equation)

14/ 5 y+14+−14=28+−14   (Add -14 to both sides)

14/ 5 y=14

14/ 5 y/ 14/ 5 = 14/ 14/ 5

(Divide both sides by 14/5)

y=5

Step: Substitute 5 for y in x= −3/ 5 y+7:

x= −3/ 5 y+7

x= −3/ 5 (5)+7

x=4  (Simplify both sides of the equation)

x=4 and y=5

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.