The area of a square in square feet is repersented by

Find an expression for a side length of the square.

Find the perimeter of the square when z=12.​

1. Find an expression for a side length of the square.

For this case, the first thing to do is to know that the area of a square is:

A = L ^ 2

Where

L: side of the square.

We then have to factorize the given polynomial:

z ^ 2 + 12z + 36

(z + 6) * (z + 6)

Rewriting:

z ^ 2 + 12z + 36 = (z + 6) ^ 2

The side of the square is:

L = (z + 6)

2. Find the perimeter when z = 12.

The perimeter of a square by definition is:

P = 4L

Where

L: side of the square.

Substituting we have:

P = 4 (z + 6)

For z = 12 we have:

P = 4 (12 + 6)

P = 72

the perimeter when z = 12 is:

P = 72

             If helpful, please mark as brainliest! =)

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )