Guadrilateral whose vertices are A(-2-2),B(5-2),C(4-3) and D(-3,-3)what kind of a guadrilatetal is ABCD?

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

The vertices of the quadrilateral ABCD are;

A(-2 -2), B(5, -2), C(4, -3)and D(-3, -3)

The slope of segment = (-2 - (-2))/(5 - (-2)) = 0

The length of segment = 5 - (-2) = 7 (points having the same y-coordinates)

The slope of segment = (-3 - (-2))/(-3 - (-2)) = 1

The length of segment = √((-3 - (-2))² + (-3 - (-2))²)  = √2

The slope of segment = (-3 - (-3))/(-3 - 4) = 0

The length of segment = 4 - (-3) = 7 (points having the same y-coordinates)

The slope of segment = (-3 - (-2))/(4 - 5) = 1

The length of segment = √((4 - 5)² + (-3 - (-2))²)  = √2

Therefore;

The opposite sites of the quadrilateral ABCD are equal; = , =

Given that the slope of a line gives the inclination of the line on a graph, we have;

The opposite sites of the quadrilateral are parallel; ║ , ║

Therefore the quadrilateral ABCD is a parallelogram because the opposite sides of the quadrilateral ABCD are parallel.

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )