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What is a difference between the sector and the segment of a circle?
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Solve the equation below: (x+4)/6x=1/x a. x=2 b. x=0,2 c. x=-2 d. x=0,-2
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Two triangles can be formed with the given information. use the law of sines to solve the triangles. b = 49°, a = 16, b = 14
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What is a difference between the sector and the segment of a circle?...
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