Consider the following five-point summary for a variable that was obtained using 200 observations. MinimumQ1MedianQ3Maximum 46667890110 a-1. Interpret Q1.
Eighty percent of the observations are less than 66, 20% of the observations are greater than 66. Seventy-five percent of the observations are less than 66, 25% of the observations are greater than 66. Twenty percent of the observations are less than 66, 80% of the observations are greater than 66. Twenty-five percent of the observations are less than 66, 75% of the observations are greater than 66.
a-2. Interpret Q3.
Eighty percent of the observations are less than 90, 20% of the observations are greater than 90. Seventy-five percent of the observations are less than 90, 25% of the observations are greater than 90. Twenty percent of the observations are less than 90, 80% of the observations are greater than 90. Twenty-five percent of the observations are less than 90, 75% of the observations are greater than 90.
b-1. Calculate the interquartile range. Interquartile range
b-2. Determine whether any outliers exist.
A. No outliers exist.
B. At least one outlier exists on the left side of the distribution.
C. At least one outlier exists on the right side of the distribution.
D. Outliers exist on both the left and right sides of the distribution.
c. Is the distribution relatively symmetric? If not, comment on its skewness. The distribution is symmetric. The distribution is positively skewed. The distribution is negatively skewed. Symmetry or skewness cannot be determined with the available information.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range:

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )