The minimum of a parabola is located at (-1, -3). The point (0, 1) is also on the graph. Which equation can be solved to determine the a value in the function representing the parabola?
O 1 = a(0 + 1)2 – 3
O 1 = a(0 - 1)2 + 3
0 0 = a[1 + 1)2-3
O 0= a1 - 1)2 + 3

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870