Calculate the vapor pressure (in torr) of a solution containing 0.2 moles of solute dissolved in 10 moles of water at 25°C. Vapor pressure of pure water at 25°C is 23.8 torr. Enter text here Enter 2021 Acellus Corporation. All Rights Reserved. C​

the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (180.2 g/mole) in 250.0 mL of water. The vapor pressure of pure water at 25°C

Step-by-step explanation:

your answer is:  22.9 torr at 25°C

Explanation:

When a non volatile solute is added to a pure solvent, the vapour pressure of the mixture decrease regard to the pure solvent following the equation

Where vapour pressure of the pure solvent (Water) is 23.8torr at 25°C.

Mole fraction of water is the ratio between moles of water and total moles in solution. The solution has a mole fraction of water of:

Replacing in Raoult's law:

Vapor pressure of the solution is 22.9 torr at 25°C

hope this helps!

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation:

first one because it can't have a fraction in it

step-by-step explanation: