Point T is on line segment S
U
‾
SU
. Given
S
U
=
5
x
,
SU=5x,
T
U
=
2
x
,
TU=2x, and
S
T
=
4
x
−
3
,
ST=4x−3, determine the numerical length of
T
U
‾
.
TU
.

Numerical length of TU = 6

Step-by-step explanation:

A/q,

SU = ST+TU

5x = 4x-3 + 2x

5x = 4x+2x-3

5x = 6x -3

5x-6x = -3

-x = -3

x = 3

Verify:- Putting x = 3 in 5x =4x-3+2x

5(3) = 4(3)-3+2(3)

15 = 12-3+6

15= 9+6

15= 15

LHS =RHS Hence correct

12*c

step-by-step explanation:

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2