If mZMRJ = 75°, then what is mZKRL?
3/2
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mZKRL =
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1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.

the answer is c.

perimeters = 3√10/5

areas = 90/25

i got it down chief.