Solve the equation for x.
x2 = 36
The solutions to the equation are
and

x2=36

We move all terms to the left:

x2-(36)=0

We add all the numbers together, and all the variables

x^2-36=0

a = 1; b = 0; c = -36;

Δ = b2-4ac

Δ = 02-4·1·(-36)

Δ = 144

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

x1=−b−Δ√2ax2=−b+Δ√2a

Δ‾‾√=144‾‾‾‾√=12

x1=−b−Δ√2a=−(0)−122∗1=−122=−6

x2=−b+Δ√2a=−(0)+122∗1=122=6

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  x = -6 or +6

Step-by-step explanation:

You know from your multiplication tables that 6×6 = 36, so one answer is ...

  x = 6

You also know that the product of two negative numbers is positive, so another answer is ...

  x = -6

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Check

  x² = 6² = 6×6 = 36

  x² = (-6)² = (-6)×(-6) = 36

Alternate approach

If you like, you can rewrite the equation as ...

  x² -36 = 0

This can be factored to ...

  (x -6)(x +6) = 0

The zero product rule tells you this product will only be zero if one or the other factors is zero.

  x -6 = 0   ⇒   x = 6

  x +6 = 0   ⇒   x = -6

The two solutions are x = ±6.

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation: