Find the equation of the parabola with its focus at (6,2) and its directrix y = 0. Question 20 options: A) y = 4(x – 6)2 + 1 B) y = –1∕4(x – 6)2 + 1 C) y = 1∕4(x – 1)2 + 6 D) y = 1∕4(x – 6)2 + 1

it’s supposed to be -4+45=41

step-by-step explanation:

you can use a^2+ b^2=c^2

i think it’s a i believe

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6