An economics professor gave her class two tests. 25% of the class passed both tests, and 48% of the class passed the first test. What percent of those who passed the first test also passed the second test? (Round to four decimal places)

9514 1404 393

  52.0833%

Step-by-step explanation:

The conditional probability formula applies.

  P(2|1) = P(2&1)/P(1)

  P(2|1) = 0.25/0.48 ≈ 0.520833

About 52.0833% of those who passed the first test also passed the second.

Comment on wording

As a fraction rounded to 4 decimal places, the value would be 0.5208 or 52.08%. This seems to ask for the percentage to be rounded to 4 decimal places, so it is 52.0833%.

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify