Jon has to choose which variable to solve for in order to be able to do the problem below in the most efficient manner. 6x+ 3y - 27
5x+ 2y - 21
Which variable should he choose so that he can use substitution to solve the system?
O Jon should solve for y in the first equation because the coefficients can be reduced by a common factor to
eliminate the coefficient for y.
•
Jon should solve for x in the first equation because the coefficients can be reduced by a common factor to
eliminate the coefficient for x.
Jon should solve for y in the second equation because the coefficients can be reduced by a common factor to
eliminate the coefficient for y.
© Jon should solve for x in the second equation because the coefficients can be reduced by a common factor to
eliminate the coefficient for x.

answer: y=0 if that is what u r looking for

the answer is d

for problems like this theres an app, its photomath that explains the problem and gives the answer hope i

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

ask i dont know either ; (

step-by-step explanation: