Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For one performance, 35 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $1675. What was the price of each kind of
ticket?

Set up a set of 2 equations in 2 variables -

Let x = advance ticket cost and y = same-day tickets cost

Then

x+y=40 and

25x+30y=1075 >>>>> 5x+6y=215

x=40-y, so

5(40-y)+6y=215

200-5y+6y=215

y=15 >>>> x=25

5(25) + 6(15) = 125+90 = 215

Check!

Step-by-step explanation:

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation: