(3x^ 2 +2xy+7)-(6x^ 2 -4xy+3)

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

 6•(x2))•y)+(x2))-(2x•(y2)))-(((5x•(y2))-7y)+3x2)

STEP  

2

:

Equation at the end of step

2

:

 6•(x2))•y)+(x2))-(2x•(y2)))-((5xy2-7y)+3x2)

STEP  

3

:

Equation at the end of step

3

:

 6•(x2))•y)+(x2))-2xy2)-(3x2+5xy2-7y)

STEP  

4

:

Equation at the end of step

4

:

 2•3x2) • y) +  x2) -  2xy2) -  (3x2 + 5xy2 - 7y)

STEP

5

:

Final result :

 6x2y - 2x2 - 7xy2 + 7y

a

step-by-step explanation:

a

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse