What is the equation of the line that passes through the point (-2,0) and has a
slope of -2?

y=-2x-4

Step-by-step explanation:

y-y1=m(x-x1)

y-0=-2(x-(-2))

y-0=-2(x+2)

y=-2x-4+0

y=-2x-4

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

what "following statement"?

step-by-step explanation: