40% of a number is 8 more than the number itself. Find this number.

Let a number be n

40% of the number = 40% of n

According to the problem given,

40% of a number is added to 42 the result is the number itself

40% of n + 42 = n

40% × n + 42=n

Therefore,

Required number = n = 70

Step-by-step explanation:

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

2/5

step-by-step explanation: