Augustus draws tickets one at a time for a raffle. The person named on the ticket must be present to win, but 30% of the 750 raffle tickets have the names of people who are no longer present. Let T be the number of tickets Augustus needs to draw to find a winner who is present. Find the probability that Augustus first draws the name of someone present on the 3rd ticket. I saw someone ask this exact question earlier and got 0.063 but none of the multiple choice is 0.063

Options
0.147
0.30
0.21
0.027
0.70

sine

step-by-step explanation:

hard

step-by-step explanation:

on the middle line

step-by-step explanation:

1/5=50

x^2 + 81

we can factor this using difference of square binomials.

rewrite the equation:

x^2 - (-81)

factor:

(a^2 - b^2) = (√a^2 + √b^2)(√a^2 - √b^2)

(x^2 - (-81) = (x + √-81)(x - √-81)

we can remove the - from under the radical by multiplying it by i.

(x^2 - (-81) = (x + i√81)(x - i√81)

(x^2 - (-81) = (x + 9i)(x - 9i)

we can check our answer by using foil:

x^2 - 9ix + 9ix - 81i^2

x^2 - 81^2

i^2 = -1

x^2 + 81