a survery or 400 randomly selected homes from a large city with over 30000 homes showed thst 16 of the sampled homes didnt have a television. based on this sample which of the following is a 95% confidence interval for the proportion of homes in this city thst dint have a television

0.0208<p<0.0592

Step-by-step explanation:

-Given the sample size is 400 and the desired proportion is 16.

-The confidence interval can be determined as follows:

#We the use this proportion to find the CI at 95%:

Hence, the 95% confidence interval is 0.0208<p<0.0592

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: