Help with both questions please <3

Step-by-step explanation:

Part A

A square pyramid surface area can be calculated using A = Lw (which gives you surface area of the base square) & 4 of A = bh/2 (which gives you surface area of the 4 triangles on the side)

This means overall A = Lw + 4(bh/2)

Length = L = 4"

Width = w = 4"

Base = b = w = L = 4"

Height = h = 6"

A = Lw + 4(bh/2)

A = Lw + 2bh     This is the answer after simplifying

A = (4")(4") + 2(4")(6")      This is the numerical expression.

A = 16" + 48" = 64"    This is the numerical answer.

A square prism surface area can be found using 2 of A = Lw (which represents the surface area of the 2 squares) and 4 of A = Lh (which gives you the surface area of the 4 rectangles).

This means overall A = 2Lw + 4Lh

Length = L = 4"

Width = w = 4"

Height = h = 6"

A = 2Lw + 4Lh

A = 2(4")(4") + 4(4")(6")    This is the numerical expression.

A = 128"     This is the numerical answer.

Part B

To see the difference between the 2 polyhedrons, I will place them as follows.

Pyramid Area = A = (4")(4") + 2(4")(6")

Prism Area = A = 2(4")(4") + 4(4")(6")

The numerical expression shows that the surface area of the prism has one more square area (as represented by 4"x4"), and has 2 more rectangular area (as represented by 4"x6").

The difference of the 2 numerical expressions can be found using subtraction:

A = [2(4")(4") + 4(4")(6")] - [(4")(4") + 2(4")(6")]

A = (4")(4") + 2(4")(6")

Hope this helps.

bn,mn,n.vn.

step-by-step explanation:

35 is an outlier

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