The vegetable garden has 95 ripe plants. The number of tomatoes is 16 fewer than twice the number of squashes. How many of each vegetable are ripe?​

Tomatoes = 39.5

Squash = 55.5

Step-by-step explanation:

T (tomatoes) = S - 16

S + T = 95

we plug it in now

S + (S - 16) = 95

2s = 95 + 16

2s = 111

s = 55.5??

hm. Let's go with it

T = 55.5 - 16

T = 39.5

39.5 + 55.5 = 95

I...guess?

i agree because i see the other persons thinking is clear

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)