In 2010 in the same country, the probability that a birth would result in twins was 0.0335, and the probability that a birth would result in triplets or more was 0.0015. What was the probability that a birth in 2010 resulted in a single child? (Assume that the probability of a birth resulting in four or more children is essentially zero.)

i think the answer is c sorry if it's wrong

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10

the first domain and range set to the left is matched with the top relation, and the second set the set in the middle goes with the bottom relation.