A used car is listed for sale at $9000. The price of the car is reduced by 20% for a quick sale. Then it is reduced by 20% of the sale price. What is the final price of the car?

7,000

Step-by-step explanation:

$5,760

Step-by-step explanation:

Start by converting 20% to a decimal, by dividing by 100 = 0.20

Then, multiply 9,000 x 0.20 = 1,800 to get the amount taken off by the sale.

9,000 - 1,800 = 7,200, the first sale price.

Multiply 7,200 by 0.20 = 1,440 to get the amount of the second discount.

7,200 - 1,440 = $5,760, the final price of the car.

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560