Martina read that approximately 10% of all people are left-handed. She wants to design a simulation to approximate the probability of selecting exactly 2 right-handed people when 3 people are randomly selected. Martina spins the arrow on the spinner 3 times and records the resulting letters. Martina performs the simulation 30 times. The results of the simulation are shown.

RRR RLR RRR RRL RRR RRR
RRR RRR RRR LRR RRR RRR
RRR RRR RRR RRR RLR LRL
RRR RRL RRR RRR LLR RRR
RRR RRR LRR RRR RRR RRR
Based on the results of this simulation, when 3 people are randomly selected, exactly 2 right-handed people are selected approximately of the time.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

- both graphs increase on their domain.

- the graphs of both functions have the same x-intercept.

- neither graph has a y-intercept.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

beluga wheeeaaalle matt

step-by-step explanation: