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(ax – 7)(bx + 5) = 6x2 + cx – 35. If ab=6 and a-b=-1 what are two possible values of c?
Answers: 1
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(ax – 7)(bx + 5) = 6x2 + cx – 35. If ab=6 and a-b=-1 what are two possible values of c?...
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