The perimeter of the rectangle is 72cm. The width of he rectangle is 8cm greater than the length. Find the width and the length.

perimeter = 72 cm

width = x

length = x+8

perimeter of rect. = 2(l+b)

2(x+x+8) = 72

2(2x+8) = 72

4x + 16 = 72

4x = 56

x = 56|4

x= 14

hence width is 14 so ,length will

14+ 8 = 22

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