The diagonals of quadrilateral EFGH intersect at D(-1,3). EFGH has vertices at E(3,6) and F(-2,4). What must be the coordinates of G and H to ensure that EFGH is a parallelogram? The coordinates of G must be... ? ( type and order pair)

Therefore the coordinates of G and H must be..?

the answer is 0.000652422

but if you ment to ask what is 6131 divided by 4, it is 1532.75.

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629