An advertising agency notices that approximately 1 in 50 potential buyers of a product ssees a given magazine ad, and 1 in 5 sees a corresponding ad on television. One in 100 see both. One in 3 actually purchases the product after seeing the ad, 1 in 10 without seeing it. What is the probability that a randomly selected potential customer will purchase the product

0.1490 = 14.90% probability that a randomly selected potential customer will purchase the product.

Step-by-step explanation:

Probability of seeing the ad:

I am going to find this probability using Venn Sets.

I am going to say that:

Event A: Sees a magazine ad.

Event B: Sees a television ad.

Approximately 1 in 50 potential buyers of a product sees a given magazine ad

This means that

1 in 5 sees a corresponding ad on television.

This means that

One in 100 see both.

This means that

The probability of seeing the ad is the probability of seeing at least one of those(magazine or tv), which is:

. So

Probability of purchasing the product.

0.21 = 21% of customers see the add. Of those, 1/3 = 0.3333 buy the product.

1 - 0.21 = 0.79 = 79% of customers dont see the add. Of those, 1/10 = 0.1 buy the product. So

0.1490 = 14.90% probability that a randomly selected potential customer will purchase the product.

where are the images of the functions i can only see the question you typed.

step-by-step explanation: