Find the midpoint of the segment whose endpoints are H (8,2) and K (2,14)

Step-by-step explanation:

take the average of the x-coordinate, and the average of the y-coordinates.

average of x-coordinates = (8+2)/2 = 5

average of y-coordinates = (2+14)/2 = 8

midpoint of HK = (5,8)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

is this part of a question or something