I need help on number 6 and 7

1. c=13

2. a=12

Step-by-step explanation:

We have to use the Pythagorean theorm

a^2+b^2=c^2

(5*5)+(12*12)=c^2

25+144=c^2

169=c^2

Now we have to square root 169 to find c

c=13

For this one we have to do c^2-b^2=A^2

(15*15)-(9*9)

225-81=a^2

144=a^2

a=12

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.