? Quadrilateral ABCD has vertices A(-2, 3), B(0,4), C(3,6), and D(1,1). The
vertices of quadrilateral EFGH are E(-2, -3), FO, -4), G(3, -6), and H(1,-1). Which
single transformation of quadrilateral ABCD can be used to show that the two
quadrilaterals are congruent?
O
a 90° counterclockwise rotation about point B
a reflection across the x-axis
O
a translation 6 units down
a reflection across the y-axis

15 units use socratic

step-by-step explanation: 15 units

4x and 6y

im not sure though

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

c

step-by-step explanation: