Question 2 15 pts
A jogger ran 6 miles due east of his house. Then he ran 4 miles at a heading of 30° East of North (or
30° NE). How far is he from his house after running 10 miles?
52 - 243
O 27
O 8
/76

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

sry but any answer choices

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )