Here is a balanced hanger. 1. Write an equation representing this hanger.
2. Find the weight of one circle. Show or explain how you found it.
25

8/3

Step-by-step explanation:

3x+4=12

find what x equals

subtract 4 on both sides (+4-4=0) (12+4=16)

then we have 3x=16

divide 16 by 3 = 8/3 (simplest form)

check-       3(8/3) + 4=12

                   ^=8+4=12

                         ^=12=12    so the answer is 8/3    i hoped this helped!

mark me brainliest

the weight of one circle is 6.25

Step-by-step explanation:

25 divided by 4=6.25

Check:

6.25x4=25

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°