The sum of three numbers is 41. The third number is five more than three-fourths of the second number. If the first number is half of the second number, what is the value of the third number?

Step-by-step explanation:

Givens

Let the first number be x / 2

Let the second number = x

Let the third number = 3/4 x + 5

Equation

x/2 + x + 3/4 x + 5 = 41                    Multiply through by 4

Solution

2x + 4x + 3x + 20 = 164                  Combine like terms on the left

9x + 20 = 164                                  Subtract 20 from both sides.

9x + 20 - 20 = 164 - 20

9x = 144                                           Divide by 9

9x/9 = 144/9

x = 16

Answer

The first number is 16/2 =                          8

The second number is   =                         16

The Third number = 3/4*16+ 5 = 12 + 5 = 17

The sum =                                                  41

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18