A rectangular box has the dimensions shown in the diagram. The volume of the box is given by the function V(x) = x3 – 4x, where x is the height in inches. What is the height of the box if the volume is 15 in.3?

length, width, and height are (b+2), (b-2), (b+3)

Step-by-step explanation:

Doing what the problem statement tells you to do, you get ...

(b^3 +3b^2) -(4b +12)

= b^2(b +3) -4(b +3) . . . . . factor each pair of terms

= (b^2 -4)(b +3) . . . . . . . . . write as a product

= (b -2)(b +2)(b +3) . . . . . . use the factoring of the difference of squares

The three factors are (b-2), (b+2), and (b+3). We have no clue as to how to associate those with length, width, and height. We just know these are the dimensions of the box.

so, converting firstly the mixed fractions to improper fractions and then "adding".

0,0

step-by-step explanation: