Mrs. Kimbell made 514 dozen brownies for the school bake sale. At the end of the bake sale, she had 212 dozen brownies left. How many brownies did she sell at the bake sale?

28 Brownies and 38 Cookies

Let say the brownies sold for B amount and cookies for C amount. There were 10 more cookies sold than brownies. If brownies sold X piece then, total sales would be:

Sales: (X+10) C + XB

Total sales is $40. Cookies sold for $0.50 each. Brownies sold for $0.75 each. If you insert it all to the first equation, it would become:

$40= (X+10) x $0.50 + $0.75X

$40= $0.50X + $5 + $0.75X

40= 1.25X + 5

1.25X= 35

X= 35 / 1.25= 28

Brownies sold at 28 pieces. Cookies sold at: 26+10= 38 pieces

Step-by-step explanation:

3,624

Step-by-step explanation:

To answer, keep in mind that a dozen equals 12.

For the first step, we could solve this 2 ways, which are to either find the total amount of the brownies by multiplying both number given by 12, or we could save that as the last step, which is what we're going to do. So, right now, we can just subtract 514 by 212:

514 - 212 = 302

Now, we multiply this number by 12 because the problem stated that she made 514 dozen and she had 212 dozen brownies remaning:

302 * 12 = 3,624

So, Mrs. Kimbell sold 302 dozen brownies, or 3,624

Hope this helps :)