The perimeter of a rectangular field is 628m. the length of the field exceeds its width by 6m. find the dimensions​

154m , 160m

Step-by-step explanation:

Let width of the rectangle = w

Length = w + 6

Perimeter of rectangle = 628 m

2( length + width ) = 628

2( w + 6 + w) = 628        {Combine like terms}

2*( 2w +6 ) = 628            {Distributive property}

2*2w + 2*6 = 628

4w + 12 = 628         {subtract 12 from both sides}

        4w = 628 - 12

        4w = 616       {Divide both sides by 4}

        w = 616/4

       w = 154 m

Length = w + 6 = 154 + 6 = 160 m