Given the points M(−6,−4) and T(9,16) find the y-coordinate of the point Q on the directed line segment MT so that MQ:QT=2:3.

8

Step-by-step explanation:

Given the coordinates M (-6, -4) and T (9, 16)

If the coordinates are divided in the ratio 2:3 then a = 2, b = 3

The y coordinate of the point Q will be expressed as;

Y = ay1+by2/a+b

From the coordinates, y1 = -4 y2 = 16

Y = 2(-4)+3(16)/2+3

Y = -8+48/5

Y = 40/5

Y = 8

Hence the y-coordinate of the point Q is 8

i think the answer is b

answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?

step-by-step explanation: