A quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, to the nearest hundredth? please help

7569.36

Step-by-step explanation:

Given that a quantity with an initial value of 7800 decays continuously at a rate of 0.1% per hour. What is the value of the quantity after 1.25 days, 

First convert 1.25 days to hours

1.25 × 24 = 30 hours

Using exponential equation

N = No ( 1 - R% )^t

Where N = new value of the quantity

No = initial value

R = rate

t = time

N = 7800 ( 1 - 0.001 )^30

N = 7800 ( 0.999 )^30

N = 7800 × 0.97043

N = 7569.36154

N = 7569.36 to the nearest hundredth.

Therefore, the value of the quantity after 1.25 days is 7569.36

8(-10x+3.5y-7)

8×-10x + 8×3.5y + 8×-7

-80x + 28y - 56

therefore

-80x+28y-56 is the correct answer